engineering mathematics MCQ #667

If y = x³ e^(x), then dy/dx = ?

engineering mathematics MCQ #667

  1. Question 1

    Q1. If y = x³ e^(x), then dy/dx = ?

    • A) x³ e^(x) + 3x² e^(x)
    • B) x³ e^(x) - 3x² e^(x)
    • C) 3x² e^(x)
    • D) x³ e^(x)

    Answer: x³ e^(x) + 3x² e^(x)

    Explanation: Using product rule, dy/dx = x³ d(e^(x))/dx + e^(x) d(x³)/dx = x³ e^(x) + e^(x) 3x² = x³ e^(x) + 3x² e^(x)