engineering mathematics MCQ #668

If y = sin(1 / x), then dy/dx = ?

engineering mathematics MCQ #668

  1. Question 1

    Q1. If y = sin(1 / x), then dy/dx = ?

    • A) -1/x² cos(1/x)
    • B) 1/x² cos(1/x)
    • C) -cos(1/x)
    • D) cos(1/x)

    Answer: -1/x² cos(1/x)

    Explanation: Using chain rule, dy/dx = cos(1/x) * d(1/x)/dx = cos(1/x) * (-1/x²) = -1/x² cos(1/x)