engineering mathematics MCQ #671

If y = x³ + 2x² - 3x + 1, then dy/dx = ?

engineering mathematics MCQ #671

  1. Question 1

    Q1. If y = x³ + 2x² - 3x + 1, then dy/dx = ?

    • A) 3x² + 4x - 3
    • B) 3x² + 2x - 3
    • C) x² + 4x - 3
    • D) 3x² - 4x + 3

    Answer: 3x² + 4x - 3

    Explanation: Using power rule for differentiation, dy/dx = d(x³)/dx + d(2x²)/dx - d(3x)/dx + d(1)/dx = 3x² + 4x - 3.