engineering mathematics MCQ #677

If y = ln(x + √(x² + 1)), then dy/dx = ?

engineering mathematics MCQ #677

  1. Question 1

    Q1. If y = ln(x + √(x² + 1)), then dy/dx = ?

    • A) 1 / √(x² + 1)
    • B) 1 / (x + √(x² + 1))
    • C) x / √(x² + 1)
    • D) 1 / (x² + 1)

    Answer: 1 / √(x² + 1)

    Explanation: Using chain rule, dy/dx = 1/(x + √(x²+1)) * d(x + √(x²+1))/dx = 1/√(x²+1).