engineering mathematics MCQ #681

If y = sin(2x)cos(x), then dy/dx = ?

engineering mathematics MCQ #681

  1. Question 1

    Q1. If y = sin(2x)cos(x), then dy/dx = ?

    • A) 2cos(2x)cos(x) - sin(2x)sin(x)
    • B) 2cos(2x)cos(x) + sin(2x)sin(x)
    • C) cos(2x)cos(x) - sin(2x)sin(x)
    • D) cos(2x)cos(x) + sin(2x)sin(x)

    Answer: 2cos(2x)cos(x) - sin(2x)sin(x)

    Explanation: Using product rule and chain rule, dy/dx = d(sin(2x))/dx * cos(x) + sin(2x) * d(cos(x))/dx = 2cos(2x)cos(x) - sin(2x)sin(x).