engineering mathematics MCQ #687

If y = x³ - 2x² + x - 1, then dy/dx at x = 1 = ?

engineering mathematics MCQ #687

  1. Question 1

    Q1. If y = x³ - 2x² + x - 1, then dy/dx at x = 1 = ?

    • A) 0
    • B) 1
    • C) 2
    • D) 3

    Answer: 2

    Explanation: First, find dy/dx = 3x² - 4x + 1, then substitute x = 1 to get 3 - 4 + 1 = 0, no, it's 3(1)² - 4(1) + 1 = 0, the correct calculation is 3 - 4 + 1 = 0.