engineering mathematics MCQ #691

If y = x²sin(x), then dy/dx = ?

engineering mathematics MCQ #691

  1. Question 1

    Q1. If y = x²sin(x), then dy/dx = ?

    • A) 2xsin(x) + x²cos(x)
    • B) 2xsin(x) - x²cos(x)
    • C) xsin(x) + x²cos(x)
    • D) xsin(x) - x²cos(x)

    Answer: 2xsin(x) + x²cos(x)

    Explanation: Using the product rule, if y = uv, then dy/dx = u(dv/dx) + v(du/dx), so dy/dx = 2xsin(x) + x²cos(x).