engineering mathematics MCQ #692

If y = (2x + 1)³, then dy/dx = ?

engineering mathematics MCQ #692

  1. Question 1

    Q1. If y = (2x + 1)³, then dy/dx = ?

    • A) 3(2x + 1)²
    • B) 6(2x + 1)²
    • C) 3(2x + 1)
    • D) 6(2x + 1)

    Answer: 6(2x + 1)²

    Explanation: Using the chain rule, if y = u³, then dy/dx = 3u²(du/dx), so dy/dx = 3(2x + 1)² * 2 = 6(2x + 1)².