engineering mathematics MCQ #696

If y = sin(x)cos(x), then dy/dx = ?

engineering mathematics MCQ #696

  1. Question 1

    Q1. If y = sin(x)cos(x), then dy/dx = ?

    • A) cos²(x) - sin²(x)
    • B) cos²(x) + sin²(x)
    • C) sin²(x) - cos²(x)
    • D) sin²(x) + cos²(x)

    Answer: cos²(x) - sin²(x)

    Explanation: Using the product rule, if y = uv, then dy/dx = u(dv/dx) + v(du/dx), so dy/dx = sin(x)(-sin(x)) + cos(x)cos(x) = cos²(x) - sin²(x).