engineering mathematics MCQ #699

If y = ln(x²), then dy/dx = ?

engineering mathematics MCQ #699

  1. Question 1

    Q1. If y = ln(x²), then dy/dx = ?

    • A) 2 / x
    • B) -2 / x
    • C) 1 / x
    • D) -1 / x

    Answer: 2 / x

    Explanation: Using the chain rule, if y = ln(u), then dy/dx = (1/u)(du/dx), so dy/dx = (1/x²)(2x) = 2/x.