engineering mathematics MCQ #701

If y = sin(3x), then dy/dx = ?

engineering mathematics MCQ #701

  1. Question 1

    Q1. If y = sin(3x), then dy/dx = ?

    • A) 3cos(3x)
    • B) -3cos(3x)
    • C) 3sin(3x)
    • D) -3sin(3x)

    Answer: 3cos(3x)

    Explanation: Using the chain rule, if y = sin(u), then dy/dx = cos(u)(du/dx), so dy/dx = cos(3x)(3) = 3cos(3x).