engineering mathematics MCQ #709

If y = (x² + 1)/(x + 1), then dy/dx = ?

engineering mathematics MCQ #709

  1. Question 1

    Q1. If y = (x² + 1)/(x + 1), then dy/dx = ?

    • A) (x + 1)(2x) - (x² + 1)(1)/(x + 1)²
    • B) (x + 1)(2x) + (x² + 1)(1)/(x + 1)²
    • C) (x² + 1)(1) - (x + 1)(2x)/(x + 1)²
    • D) (x² + 1)(1) + (x + 1)(2x)/(x + 1)²

    Answer: (x + 1)(2x) - (x² + 1)(1)/(x + 1)²

    Explanation: Using the quotient rule, if y = u/v, then dy/dx = (v(du/dx) - u(dv/dx))/v², here u = x² + 1, v = x + 1.