engineering mathematics MCQ #742

If y = x²e^x, then dy/dx = ?

engineering mathematics MCQ #742

  1. Question 1

    Q1. If y = x²e^x, then dy/dx = ?

    • A) x²e^x + 2xe^x
    • B) x²e^x - 2xe^x
    • C) 2xe^x - x²e^x
    • D) 2xe^x + x²e^x

    Answer: x²e^x + 2xe^x

    Explanation: Using the product rule, if y = u*v, then dy/dx = u*dv/dx + v*du/dx, here u = x², v = e^x.