engineering mathematics MCQ #743

If y = sin(3x), then d²y/dx² = ?

engineering mathematics MCQ #743

  1. Question 1

    Q1. If y = sin(3x), then d²y/dx² = ?

    • A) -9sin(3x)
    • B) 9sin(3x)
    • C) -3sin(3x)
    • D) 3sin(3x)

    Answer: -9sin(3x)

    Explanation: First derivative is 3cos(3x), and the second derivative is -3*3sin(3x) = -9sin(3x), using the chain rule.