engineering mathematics MCQ #754

If y = ln(x² + 1), then dy/dx = ?

engineering mathematics MCQ #754

  1. Question 1

    Q1. If y = ln(x² + 1), then dy/dx = ?

    • A) 2x / (x² + 1)
    • B) x / (x² + 1)
    • C) 2 / (x² + 1)
    • D) 1 / (x² + 1)

    Answer: 2x / (x² + 1)

    Explanation: Using chain rule, dy/dx = d(ln(x² + 1))/dx = 1/(x² + 1) * d(x² + 1)/dx = 1/(x² + 1) * 2x = 2x / (x² + 1).