engineering mathematics MCQ #757

If y = cos(x³), then dy/dx = ?

engineering mathematics MCQ #757

  1. Question 1

    Q1. If y = cos(x³), then dy/dx = ?

    • A) -3x² sin(x³)
    • B) 3x² sin(x³)
    • C) -sin(x³)
    • D) sin(x³)

    Answer: -3x² sin(x³)

    Explanation: Using chain rule, dy/dx = d(cos(x³))/dx = -sin(x³) * d(x³)/dx = -sin(x³) * 3x² = -3x² sin(x³).