engineering mathematics MCQ #758

If y = (sin(x))², then dy/dx = ?

engineering mathematics MCQ #758

  1. Question 1

    Q1. If y = (sin(x))², then dy/dx = ?

    • A) 2 sin(x) cos(x)
    • B) sin(x) cos(x)
    • C) 2 cos(x)
    • D) sin(2x)

    Answer: 2 sin(x) cos(x)

    Explanation: Using chain rule, dy/dx = d((sin(x))²)/dx = 2 sin(x) * d(sin(x))/dx = 2 sin(x) * cos(x) = 2 sin(x) cos(x).