engineering mathematics MCQ #761

If y = (x² + 1) / (x + 1), then dy/dx = ?

engineering mathematics MCQ #761

  1. Question 1

    Q1. If y = (x² + 1) / (x + 1), then dy/dx = ?

    • A) (x² + 2x - 1) / (x + 1)²
    • B) (x² + 2x + 1) / (x + 1)²
    • C) (x + 1) / (x² + 1)
    • D) (x² - 1) / (x + 1)²

    Answer: (x² + 2x - 1) / (x + 1)²

    Explanation: Using quotient rule, dy/dx = ((x+1)d(x²+1)/dx - (x²+1)d(x+1)/dx) / (x+1)² = ((x+1)*2x - (x²+1)*1) / (x+1)² = (2x² + 2x - x² - 1) / (x+1)² = (x² + 2x - 1) / (x+1)².