engineering mathematics MCQ #762

If y = sin(x) cos(x), then dy/dx = ?

engineering mathematics MCQ #762

  1. Question 1

    Q1. If y = sin(x) cos(x), then dy/dx = ?

    • A) cos²(x) - sin²(x)
    • B) cos²(x) + sin²(x)
    • C) sin(x) + cos(x)
    • D) sin(x) - cos(x)

    Answer: cos²(x) - sin²(x)

    Explanation: Using product rule, dy/dx = d(sin(x)cos(x))/dx = sin(x)d(cos(x))/dx + cos(x)d(sin(x))/dx = sin(x)*(-sin(x)) + cos(x)*cos(x) = cos²(x) - sin²(x).