engineering mathematics MCQ #773

Find the derivative of y = sin(1 / x)

engineering mathematics MCQ #773

  1. Question 1

    Q1. Find the derivative of y = sin(1 / x)

    • A) -1/x² cos(1 / x)
    • B) 1/x² cos(1 / x)
    • C) -cos(1 / x) / x
    • D) cos(1 / x) / x

    Answer: -1/x² cos(1 / x)

    Explanation: Using the chain rule, dy/dx = cos(1/x) * d(1/x)/dx = cos(1/x) * (-1/x²) = -1/x² cos(1 / x)