engineering mathematics MCQ #778

If y = ln(x + √(x² + 1)), find dy/dx

engineering mathematics MCQ #778

  1. Question 1

    Q1. If y = ln(x + √(x² + 1)), find dy/dx

    • A) 1 / √(x² + 1)
    • B) 1 / (x + √(x² + 1))
    • C) x / √(x² + 1)
    • D) (x + 1) / √(x² + 1)

    Answer: 1 / √(x² + 1)

    Explanation: Using the chain rule, dy/dx = 1/(x + √(x² + 1)) * d(x + √(x² + 1))/dx = 1/(x + √(x² + 1)) * (1 + x/√(x² + 1)) = 1 / √(x² + 1)