engineering mathematics MCQ #780

If y = (x + √(x² + 1))³, find dy/dx

engineering mathematics MCQ #780

  1. Question 1

    Q1. If y = (x + √(x² + 1))³, find dy/dx

    • A) 3(x + √(x² + 1))² (1 + x/√(x² + 1))
    • B) 3(x + √(x² + 1))²
    • C) (x + √(x² + 1))² (1 + x/√(x² + 1))
    • D) (x + √(x² + 1)) (1 + x/√(x² + 1))

    Answer: 3(x + √(x² + 1))² (1 + x/√(x² + 1))

    Explanation: Using the chain rule, dy/dx = 3(x + √(x² + 1))² * d(x + √(x² + 1))/dx = 3(x + √(x² + 1))² * (1 + x/√(x² + 1))