engineering mathematics MCQ #784

If y = ln(2x + 1), then dy/dx = ?

engineering mathematics MCQ #784

  1. Question 1

    Q1. If y = ln(2x + 1), then dy/dx = ?

    • A) 2 / (2x + 1)
    • B) 1 / (2x + 1)
    • C) 1 / (x + 1)
    • D) 2 / (x + 1)

    Answer: 2 / (2x + 1)

    Explanation: Using the chain rule, dy/dx = d(ln(2x + 1))/dx = 1/(2x + 1) * d(2x + 1)/dx = 1/(2x + 1) * 2 = 2 / (2x + 1).