engineering mathematics MCQ #787

If y = x³ + 3x² + 2x + 1, then dy/dx = ?

engineering mathematics MCQ #787

  1. Question 1

    Q1. If y = x³ + 3x² + 2x + 1, then dy/dx = ?

    • A) 3x² + 6x + 2
    • B) x² + 2x + 1
    • C) 3x² + 2x + 2
    • D) x³ + 3x² + 2

    Answer: 3x² + 6x + 2

    Explanation: Using the power rule for differentiation, dy/dx = d(x³ + 3x² + 2x + 1)/dx = 3x² + 6x + 2.