engineering mathematics MCQ #792

If y = tan(2x + 1), then dy/dx = ?

engineering mathematics MCQ #792

  1. Question 1

    Q1. If y = tan(2x + 1), then dy/dx = ?

    • A) 2 sec²(2x + 1)
    • B) sec²(2x + 1)
    • C) 2 tan(2x + 1)
    • D) sec(2x + 1)

    Answer: 2 sec²(2x + 1)

    Explanation: Using the chain rule, dy/dx = d(tan(2x + 1))/dx = sec²(2x + 1) * d(2x + 1)/dx = sec²(2x + 1) * 2 = 2 sec²(2x + 1).