engineering mathematics MCQ #801

If y = √(x² + 1), then dy/dx = ?

engineering mathematics MCQ #801

  1. Question 1

    Q1. If y = √(x² + 1), then dy/dx = ?

    • A) x / √(x² + 1)
    • B) 2x / √(x² + 1)
    • C) x / (x² + 1)
    • D) 1 / √(x² + 1)

    Answer: x / √(x² + 1)

    Explanation: Using chain rule, dy/dx = d(√(x² + 1))/dx = 1 / (2√(x² + 1)) * d(x² + 1)/dx = 1 / (2√(x² + 1)) * 2x = x / √(x² + 1).