engineering mathematics MCQ #803

If y = sin(2x + 1), then dy/dx = ?

engineering mathematics MCQ #803

  1. Question 1

    Q1. If y = sin(2x + 1), then dy/dx = ?

    • A) 2 cos(2x + 1)
    • B) cos(2x + 1)
    • C) -2 cos(2x + 1)
    • D) -cos(2x + 1)

    Answer: 2 cos(2x + 1)

    Explanation: Using chain rule, dy/dx = d(sin(2x + 1))/dx = cos(2x + 1) * d(2x + 1)/dx = cos(2x + 1) * 2 = 2 cos(2x + 1).