engineering mathematics MCQ #804

If y = x³ e^x, then dy/dx = ?

engineering mathematics MCQ #804

  1. Question 1

    Q1. If y = x³ e^x, then dy/dx = ?

    • A) x³ e^x + 3x² e^x
    • B) x³ e^x - 3x² e^x
    • C) 3x² e^x
    • D) x³ e^x

    Answer: x³ e^x + 3x² e^x

    Explanation: Using product rule, dy/dx = d(x³ e^x)/dx = x³ * d(e^x)/dx + e^x * d(x³)/dx = x³ e^x + e^x * 3x² = x³ e^x + 3x² e^x.