engineering mathematics MCQ #805

If y = (sin(x))³, then dy/dx = ?

engineering mathematics MCQ #805

  1. Question 1

    Q1. If y = (sin(x))³, then dy/dx = ?

    • A) 3(sin(x))² cos(x)
    • B) 3(sin(x))²
    • C) (sin(x))² cos(x)
    • D) (sin(x))²

    Answer: 3(sin(x))² cos(x)

    Explanation: Using chain rule, dy/dx = d((sin(x))³)/dx = 3(sin(x))² * d(sin(x))/dx = 3(sin(x))² * cos(x) = 3(sin(x))² cos(x).