engineering mathematics MCQ #806

If y = e^(x² + 1), then dy/dx = ?

engineering mathematics MCQ #806

  1. Question 1

    Q1. If y = e^(x² + 1), then dy/dx = ?

    • A) 2x e^(x² + 1)
    • B) x e^(x² + 1)
    • C) e^(x² + 1)
    • D) 2 e^(x² + 1)

    Answer: 2x e^(x² + 1)

    Explanation: Using chain rule, dy/dx = d(e^(x² + 1))/dx = e^(x² + 1) * d(x² + 1)/dx = e^(x² + 1) * 2x = 2x e^(x² + 1).