engineering mathematics MCQ #810

If f(x) = 3x²sin(x), then f'(x) = ?

engineering mathematics MCQ #810

  1. Question 1

    Q1. If f(x) = 3x²sin(x), then f'(x) = ?

    • A) 6xsin(x) + 3x²cos(x)
    • B) 6xsin(x) - 3x²cos(x)
    • C) 3x²sin(x) + 6xcos(x)
    • D) 6xsin(x)

    Answer: 6xsin(x) + 3x²cos(x)

    Explanation: Apply the product rule: (uv)' = u'v + uv', where u = 3x² and v = sin(x), so u' = 6x and v' = cos(x).