engineering mathematics MCQ #822

If y = (3x² + 2x + 1)³, then dy/dx = ?

engineering mathematics MCQ #822

  1. Question 1

    Q1. If y = (3x² + 2x + 1)³, then dy/dx = ?

    • A) 3(3x² + 2x + 1)²(6x + 2)
    • B) 3(3x² + 2x + 1)²
    • C) (6x + 2)³
    • D) (3x² + 2x + 1)²

    Answer: 3(3x² + 2x + 1)²(6x + 2)

    Explanation: Using the chain rule, where the outer function is u³ and the inner function is u = 3x² + 2x + 1, so u' = 6x + 2.