If f(x) = x²sin(x), then f'(x) =
Question 1
Q1. If f(x) = x²sin(x), then f'(x) =
Answer: 2xsin(x) + x²cos(x)
Explanation: Using the product rule, f'(x) = d(x²)/dx * sin(x) + x² * d(sin(x))/dx = 2xsin(x) + x²cos(x).