engineering mathematics MCQ #843

If f(x) = x²e^x, then f'(x) =

engineering mathematics MCQ #843

  1. Question 1

    Q1. If f(x) = x²e^x, then f'(x) =

    • A) x²e^x + 2xe^x
    • B) x²e^x - 2xe^x
    • C) 2xe^x
    • D) x²e^x

    Answer: x²e^x + 2xe^x

    Explanation: Using the product rule, f'(x) = x²e^x + 2xe^x.