If f(x) = x²sin(x), then f'(x) is
Question 1
Q1. If f(x) = x²sin(x), then f'(x) is
Answer: 2xsin(x) + x²cos(x)
Explanation: Using product rule, f'(x) = (x²)'sin(x) + x²(sin(x))' = 2xsin(x) + x²cos(x).