engineering mathematics MCQ #857

If y = ln(x² + 1), then dy/dx is

engineering mathematics MCQ #857

  1. Question 1

    Q1. If y = ln(x² + 1), then dy/dx is

    • A) 2x / (x² + 1)
    • B) 1 / (x² + 1)
    • C) 2x / (x + 1)
    • D) x / (x² + 1)

    Answer: 2x / (x² + 1)

    Explanation: Using chain rule, if y = ln(u) and u = x² + 1, then dy/dx = 1/u * du/dx = 1/(x²+1) * 2x = 2x / (x² + 1).