A tower is 100√3 m high. Find the angle of elevation of its top from a point 100 m away from its foot.
Q1. A tower is 100√3 m high. Find the angle of elevation of its top from a point 100 m away from its foot.
Answer: 60°
Explanation: Using tan(θ) = opposite/adjacent = 100√3 / 100 = √3, so θ = 60°.