engineering mathematics MCQ #883

If y = sin(3x), find dy/dx

engineering mathematics MCQ #883

  1. Question 1

    Q1. If y = sin(3x), find dy/dx

    • A) 3cos(3x)
    • B) cos(3x)
    • C) -3cos(3x)
    • D) -cos(3x)

    Answer: 3cos(3x)

    Explanation: Using chain rule, dy/dx = cos(3x) * d(3x)/dx = 3cos(3x).