engineering mathematics MCQ #89

If sin(θ) = 3/5, find cos(θ).

engineering mathematics MCQ #89

  1. Question 1

    Q1. If sin(θ) = 3/5, find cos(θ).

    • A) 4/5
    • B) 3/4
    • C) 2/3
    • D) 1/2

    Answer: 4/5

    Explanation: Using Pythagorean identity: sin²(θ) + cos²(θ) = 1, so cos(θ) = √(1 - (3/5)²) = 4/5.