If f(x) = x³e^x, find f'(x)
Question 1
Q1. If f(x) = x³e^x, find f'(x)
Answer: x³e^x + 3x²e^x
Explanation: Use the product rule: f'(x) = (x³)'e^x + x³(e^x)' = 3x²e^x + x³e^x.