engineering mathematics MCQ #898

Differentiate f(x) = tan(3x)

engineering mathematics MCQ #898

  1. Question 1

    Q1. Differentiate f(x) = tan(3x)

    • A) 3sec²(3x)
    • B) sec²(3x)
    • C) -3sec²(3x)
    • D) -sec²(3x)

    Answer: 3sec²(3x)

    Explanation: Apply the chain rule: f'(x) = sec²(3x) * d(3x)/dx = 3sec²(3x).