engineering mathematics MCQ #905

Differentiate f(x) = (x² + 1)³

engineering mathematics MCQ #905

  1. Question 1

    Q1. Differentiate f(x) = (x² + 1)³

    • A) 6x(x² + 1)²
    • B) 3x(x² + 1)²
    • C) 3(x² + 1)²
    • D) 6(x² + 1)²

    Answer: 6x(x² + 1)²

    Explanation: Use the chain rule: f'(x) = 3(x²+1)² * d(x²+1)/dx = 3(x²+1)² * 2x = 6x(x² + 1)².