If f(x) = x²sin(x), find f'(x)
Question 1
Q1. If f(x) = x²sin(x), find f'(x)
Answer: 2xsin(x) + x²cos(x)
Explanation: Using the product rule, f'(x) = d(x²)/dx*sin(x) + x²*d(sin(x))/dx = 2xsin(x) + x²cos(x).