engineering mathematics MCQ #978

Find the derivative of f(x) = x³cos(x)

engineering mathematics MCQ #978

  1. Question 1

    Q1. Find the derivative of f(x) = x³cos(x)

    • A) 3x²cos(x) - x³sin(x)
    • B) x³sin(x)
    • C) 3x²cos(x)
    • D) x³cos(x)

    Answer: 3x²cos(x) - x³sin(x)

    Explanation: Using the product rule, f'(x) = d(x³)/dx*cos(x) + x³*d(cos(x))/dx = 3x²cos(x) - x³sin(x).