A capacitor of 100 μF is connected to an AC source. If the frequency is 50 Hz, what is its reactance?
Q1. A capacitor of 100 μF is connected to an AC source. If the frequency is 50 Hz, what is its reactance?
Answer: 31.83 Ω
Explanation: Xc = 1 / (2πfC) = 1 / (2 * π * 50 * 100 * 10^(-6)) = 31.83 Ω