The voltage across an inductor is given by V = 200 sin(100πt). What is the frequency of the AC source?
Q1. The voltage across an inductor is given by V = 200 sin(100πt). What is the frequency of the AC source?
Answer: 50 Hz
Explanation: ω = 2πf = 100π. So, f = 100π / (2π) = 50 Hz.