engineering physics MCQ #122

In an LCR series circuit, the resonance frequency is 1000 Hz. If L = 1 H, what is the value of C?

engineering physics MCQ #122

  1. Question 1

    Q1. In an LCR series circuit, the resonance frequency is 1000 Hz. If L = 1 H, what is the value of C?

    • A) 0.025 μF
    • B) 25 μF
    • C) 0.025 F
    • D) 2.5 μF

    Answer: 0.025 μF

    Explanation: At resonance, f = 1 / (2π√(LC)). So, C = 1 / (4π²f²L) = 1 / (4 * 3.14² * 1000² * 1) = 0.025 * 10^(-6) F = 0.025 μF.