engineering physics MCQ #1226

A coil of self-inductance 0.5 H has a current of 2 A. If the current is reduced to zero in 0.1 s, induced emf is

engineering physics MCQ #1226

  1. Question 1

    Q1. A coil of self-inductance 0.5 H has a current of 2 A. If the current is reduced to zero in 0.1 s, induced emf is

    • A) 5 V
    • B) 10 V
    • C) 15 V
    • D) 20 V

    Answer: 10 V

    Explanation: Induced emf = -L(dI/dt) = -0.5 * (-2 / 0.1) = 10 V.