engineering physics MCQ #1230

The self-inductance of a coil is given by L = μN²A/l. If number of turns is doubled, self-inductance becomes

engineering physics MCQ #1230

  1. Question 1

    Q1. The self-inductance of a coil is given by L = μN²A/l. If number of turns is doubled, self-inductance becomes

    • A) 2L
    • B) 4L
    • C) 8L
    • D) L/2

    Answer: 4L

    Explanation: L is proportional to N², hence doubling N makes L four times.