A coil of inductance 0.2 H is connected to a 10 V battery. If current changes at 5 A/s, find induced emf.
Q1. A coil of inductance 0.2 H is connected to a 10 V battery. If current changes at 5 A/s, find induced emf.
Answer: 1 V
Explanation: ε = -L(dI/dt) = -0.2 * 5 = 1 V.